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Pratica

Soluzione del problema di Érsek e Lindner

5R2/pK6/3pp1p1/1B1PN1p1/r3k1b1/bQPN4/R6P/6B1 w - - 0 1

SOLUZIONE:

1. Cc4 ...

A ) 1. ... a5 (a6) 2. Cd2#

B ) 1. ... Ac1 2. Cxd6#

C ) 1. ... Txc4 2. Dxc4#

D ) 1, ... Rxd3 2. Dc2#

E ) 1. ... Rxd5 2. Ac6#

F ) 1. ... exd5 2. Cf2#

G ) 1. ... Af5 2. Cd2#